2[c-4(2x+1)]=6x

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Solution for 2[c-4(2x+1)]=6x equation:


Simplifying
2[c + -4(2x + 1)] = 6x

Reorder the terms:
2[c + -4(1 + 2x)] = 6x
2[c + (1 * -4 + 2x * -4)] = 6x
2[c + (-4 + -8x)] = 6x

Reorder the terms:
2[-4 + c + -8x] = 6x
[-4 * 2 + c * 2 + -8x * 2] = 6x
[-8 + 2c + -16x] = 6x

Solving
-8 + 2c + -16x = 6x

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 2c + 8 + -16x = 8 + 6x

Reorder the terms:
-8 + 8 + 2c + -16x = 8 + 6x

Combine like terms: -8 + 8 = 0
0 + 2c + -16x = 8 + 6x
2c + -16x = 8 + 6x

Add '16x' to each side of the equation.
2c + -16x + 16x = 8 + 6x + 16x

Combine like terms: -16x + 16x = 0
2c + 0 = 8 + 6x + 16x
2c = 8 + 6x + 16x

Combine like terms: 6x + 16x = 22x
2c = 8 + 22x

Divide each side by '2'.
c = 4 + 11x

Simplifying
c = 4 + 11x

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